derivative of 230-8x+0.04x^2

Lösung

\frac{d}{d x} (230 - 8 x + 0.04 x^{2})

0.08 x - 8

Schritte zur Lösung

\frac{d}{d x} (230 - 8 x + 0.04 x^{2})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (230) - \frac{d}{d x} (8 x) + \frac{d}{d x} (0.04 x^{2})

\frac{d}{d x} (230) = 0

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (0.04 x^{2}) = 0.08 x

= 0 - 8 + 0.08 x

Vereinfache

= 0.08 x - 8

\frac{d}{d x} (\frac{csc ( x ) \cdot tan ( x )}{cos ( x )})

x \to \frac{π}{2} + lim (\frac{9}{x} sec (x))

\int \frac{5 ^{x}}{1 + 5 ^{x}} d x

im pl i c i t \frac{d y}{d x}, 16 x^{2} - 16 x y + y^{2} = 1

x \to 0 lim (x^{2} \cdot ln (x))