What is the integral of sec(x)tan(x)-4e^x ?

The integral of sec(x)tan(x)-4e^x is sec(x)-4e^x+C

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integral of sec(x)tan(x)-4e^x

\int sec (x) tan (x) - 4 e^{x} d x

sec (x) - 4 e^{x} + C

Solution steps

\int sec (x) tan (x) - 4 e^{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int sec (x) tan (x) d x - \int 4 e^{x} d x

\int sec (x) tan (x) d x = sec (x)

\int 4 e^{x} d x = 4 e^{x}

= sec (x) - 4 e^{x}

Add a constant to the solution

= sec (x) - 4 e^{x} + C

\int sinh (4 x) d x

t a y l or (1 + (\frac{1}{2}) \cdot x) - 4

t \to 0 lim (e^{5 t})

\frac{d}{d x} (e^{x^{2} - 3})

\frac{d}{d t} (10 sin (t))

What is the integral of sec(x)tan(x)-4e^x ?
The integral of sec(x)tan(x)-4e^x is sec(x)-4e^x+C