What is the derivative of sqrt(y)-7y ?

The derivative of sqrt(y)-7y is 1/(2sqrt(y))-7

What is the first derivative of sqrt(y)-7y ?

The first derivative of sqrt(y)-7y is 1/(2sqrt(y))-7

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derivative of

y - 7 y

\frac{1}{2 y} - 7

Solution steps

\frac{d}{d y} (y - 7 y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (y) - \frac{d}{d y} (7 y)

\frac{d}{d y} (y) = \frac{1}{2 y}

\frac{d}{d y} (7 y) = 7

= \frac{1}{2 y} - 7

\int_{1.5}^{2} cos (\frac{π x}{3}) d x

t a y l or sin (9 x)

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y^{^{''}} - 4 y^{^{'}} + 3 y = - e^{- s}, y (0) = 0, y^{^{'}} (0) = 0

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What is the derivative of sqrt(y)-7y ?
The derivative of sqrt(y)-7y is 1/(2sqrt(y))-7
What is the first derivative of sqrt(y)-7y ?
The first derivative of sqrt(y)-7y is 1/(2sqrt(y))-7