What is the derivative of x^2+Ax+B ?

The derivative of x^2+Ax+B is 2x+A

What is the first derivative of x^2+Ax+B ?

The first derivative of x^2+Ax+B is 2x+A

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\frac{d}{d x} (x^{2} + A x + B)

2 x + A

Solution steps

\frac{d}{d x} (x^{2} + A x + B)

Treat

A, B

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (A x) + \frac{d B}{d x}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (A x) = A

\frac{d B}{d x} = 0

= 2 x + A + 0

Simplify

= 2 x + A

\int 4 x e^{4 x} d x

\frac{d}{d x} (\frac{x ^{2}}{8} - \frac{1}{x})

\int \frac{1}{3 x ^{2} + 4} d x

t an g e n t y = 3 x + 6 cos (x), (\frac{π}{3}, π + 3)

d er i v a t i v e y = (x^{2} + 8)^{2} - 4 x

What is the derivative of x^2+Ax+B ?
The derivative of x^2+Ax+B is 2x+A
What is the first derivative of x^2+Ax+B ?
The first derivative of x^2+Ax+B is 2x+A