What is the integral from 0 to infinity of 1/(x^2) ?

The integral from 0 to infinity of 1/(x^2) is diverges

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integral from 0 to infinity of 1/(x^2)

\int_{0}^{\infty} \frac{1}{x ^{2}} d x

diverges

Solution steps

\int_{0}^{\infty} \frac{1}{x ^{2}} d x

Compute the indefinite integral:

\int \frac{1}{x ^{2}} d x = - \frac{1}{x} + C

Compute the boundaries:

\int_{0}^{\infty} \frac{1}{x ^{2}} d x =

diverges

= diverges

x \to - 6 lim (\frac{x ^{2} - 8}{6 - x})

\frac{\partial}{\partial x} (sin (- 5 x - 2 y + z))

l a pl a ce t r an s f or m x e^{- x}

\int_{0}^{\frac{π}{21}} cos (7 x) d x

d er i v a t i v e \frac{141}{7 - 2}

What is the integral from 0 to infinity of 1/(x^2) ?
The integral from 0 to infinity of 1/(x^2) is diverges