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Popular Calculus >

y= 1/((x^2-2)(x^2+x+5))

Solution

y = \frac{1}{( x ^{2} - 2 ) ( x ^{2} + x + 5 )}

Solution

Domain : x < - 2 or - 2 < x < 2 or x > 2

Range : f (x) \leq - 0.09711 \dots or f (x) > 0

Y Intercepts : (0, - \frac{1}{10})

Asymptotes : Vertical x = - 2, x = 2, Horizontal y = 0

Extreme Points : Maximum (0.27965 \dots, - 0.09711 \dots)

+1

Interval Notation

Domain : (- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Range : (- \infty, - 0.09711 \dots] \cup (0, \infty)

Solution steps

Domain of

\frac{1}{( x ^{2} - 2 ) ( x ^{2} + x + 5 )} : x < - 2 or - 2 < x < 2 or x > 2

Range of

\frac{1}{( x ^{2} - 2 ) ( x ^{2} + x + 5 )} : f (x) \leq - 0.09711 \dots or f (x) > 0

Axis interception points of

\frac{1}{( x ^{2} - 2 ) ( x ^{2} + x + 5 )} :

Y Intercepts

: (0, - \frac{1}{10})

Asymptotes of

\frac{1}{( x ^{2} - 2 ) ( x ^{2} + x + 5 )} :

Vertical

: x = - 2, x = 2,

Horizontal

: y = 0

Extreme Points of

\frac{1}{( x ^{2} - 2 ) ( x ^{2} + x + 5 )} :

Maximum

(0.27965 \dots, - 0.09711 \dots)

Graph

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Frequently Asked Questions (FAQ)

What is the y= 1/((x^2-2)(x^2+x+5)) ?
The y= 1/((x^2-2)(x^2+x+5)) is