What is inverse oflaplace k/s ?

The answer to inverse oflaplace k/s is Undefined

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inverse oflaplace k/s

inverse laplace

\frac{k}{s}

Undefined

Solution steps

L^{- 1} {\frac{k}{s}}

Apply inverse transform rule:

L^{- 1} {F (s)} = f (t)

then

L^{- 1} {s F (s)} = \frac{d}{d t} f (t) + f (0)

For

\frac{k}{s} : F (s) = \frac{1}{s}

= \frac{d}{d t} (L^{- 1} {\frac{1}{s}}) + L^{- 1} {\frac{1}{s}} (0)

L^{- 1} {\frac{1}{s}} : H (t)

Evaluate

H (t)

at point

0 =

Undefined

= Undefined

\frac{d}{d x} (cos^{2} (9 x) + sin^{2} (9 x))

\frac{d y}{d x} + \frac{y}{x ^{2} + x} = x + 1

\frac{d}{d x} (2 I n x)

ma c l a u r in 3 sin (- 2 x^{2})

x \to 0 lim ((1 + 2 x)^{\frac{1}{2 x ^{2}}})

What is inverse oflaplace k/s ?
The answer to inverse oflaplace k/s is Undefined