What is the derivative of 4x(x^2-9) ?

The derivative of 4x(x^2-9) is 4(3x^2-9)

What is the first derivative of 4x(x^2-9) ?

The first derivative of 4x(x^2-9) is 4(3x^2-9)

derivative of

4 x (x^{2} - 9)

4 (3 x^{2} - 9)

Solution steps

\frac{d}{d x} (4 x (x^{2} - 9))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (x (x^{2} - 9))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = x^{2} - 9

= 4 (\frac{d x}{d x} (x^{2} - 9) + \frac{d}{d x} (x^{2} - 9) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2} - 9) = 2 x

= 4 (1 \cdot (x^{2} - 9) + 2 xx)

Simplify

4 (1 \cdot (x^{2} - 9) + 2 xx) : 4 (3 x^{2} - 9)

= 4 (3 x^{2} - 9)

y^{^{''}} + 3 y^{^{'}} + 10 y = 0

s l o p e (- 6, - 6), (- 5, 0)

\frac{d}{d x} (x^{3} + 5 x^{2} - x^{- 2} + 8)

\frac{d}{d x} (sin^{7} (2 x))

\frac{d}{d x} (- 10 e^{- 2 x})

What is the derivative of 4x(x^2-9) ?
The derivative of 4x(x^2-9) is 4(3x^2-9)
What is the first derivative of 4x(x^2-9) ?
The first derivative of 4x(x^2-9) is 4(3x^2-9)