What is (\partial)/(\partial x)(sin^4(x-7y)) ?

The answer to (\partial)/(\partial x)(sin^4(x-7y)) is 4sin^3(x-7y)cos(x-7y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial)/(\partial x)(sin^4(x-7y))

\frac{\partial}{\partial x} (sin^{4} (x - 7 y))

4 sin^{3} (x - 7 y) cos (x - 7 y)

Solution steps

\frac{\partial}{\partial x} (sin^{4} (x - 7 y))

Treat

y

as a constant

Apply the chain rule:

4 (sin (x - 7 y))^{3} \frac{\partial}{\partial x} (sin (x - 7 y))

= 4 (sin (x - 7 y))^{3} \frac{\partial}{\partial x} (sin (x - 7 y))

\frac{\partial}{\partial x} (sin (x - 7 y)) = cos (x - 7 y)

= 4 (sin (x - 7 y))^{3} cos (x - 7 y)

Simplify

= 4 sin^{3} (x - 7 y) cos (x - 7 y)

\int 5 x d x

4 d y + y d x = x^{2} d y

y^{^{'}} = 2 x - 3 y + 1

e^{2 y} y^{^{'}} = 3

n = 0 \sum \infty (\frac{x}{4})^{n}

What is (\partial)/(\partial x)(sin^4(x-7y)) ?
The answer to (\partial)/(\partial x)(sin^4(x-7y)) is 4sin^3(x-7y)cos(x-7y)