What is the derivative of \sqrt[3]{x}+2sqrt(t^3) ?

The derivative of \sqrt[3]{x}+2sqrt(t^3) is 1/(3x^{2/3)}

What is the first derivative of \sqrt[3]{x}+2sqrt(t^3) ?

The first derivative of \sqrt[3]{x}+2sqrt(t^3) is 1/(3x^{2/3)}

\frac{d}{d x} (3 x + 2 t^{3})

\frac{1}{3 x ^{\frac{2}{3}}}

Solution steps

\frac{d}{d x} (3 x + 2 t^{3})

Treat

t

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (2 t^{3})

\frac{d}{d x} (3 x) = \frac{1}{3 x ^{\frac{2}{3}}}

\frac{d}{d x} (2 t^{3}) = 0

= \frac{1}{3 x ^{\frac{2}{3}}} + 0

Simplify

= \frac{1}{3 x ^{\frac{2}{3}}}

\frac{\partial}{\partial x} (l sin (θ))

d er i v a t i v e \frac{( cos ^{3} ( x ) - 1 )}{cos ^{2} ( x )}

11 (t + 1) y^{^{'}} - 9 y = 18 t

\frac{d}{d x} (\frac{x}{x + \frac{b}{x}})

\frac{\partial}{\partial x} (e^{x^{2 - y^{2}}})

What is the derivative of \sqrt[3]{x}+2sqrt(t^3) ?
The derivative of \sqrt[3]{x}+2sqrt(t^3) is 1/(3x^{2/3)}
What is the first derivative of \sqrt[3]{x}+2sqrt(t^3) ?
The first derivative of \sqrt[3]{x}+2sqrt(t^3) is 1/(3x^{2/3)}