What is the integral of 4/(cos^2(x)) ?

The integral of 4/(cos^2(x)) is 4tan(x)+C

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integral of 4/(cos^2(x))

\int \frac{4}{cos ^{2} ( x )} d x

4 tan (x) + C

Solution steps

\int \frac{4}{cos ^{2} ( x )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int \frac{1}{cos ^{2} ( x )} d x

Use the common integral:

\int \frac{1}{cos ^{2} ( x )} d x = tan (x)

= 4 tan (x)

Add a constant to the solution

= 4 tan (x) + C

\int e^{- p x} d x

\frac{d}{d x} (x^{\frac{2}{3}} (x + 4)^{\frac{1}{2}})

d er i v a t i v e f (x) = 8 x - x^{2}

d er i v a t i v e - x^{2} + 26 x + 920

\frac{d}{d x} (\frac{4 x - 1 + x}{x ^{2} - 1})

What is the integral of 4/(cos^2(x)) ?
The integral of 4/(cos^2(x)) is 4tan(x)+C