What is the derivative of g(u)=sqrt(6u)+sqrt(5u) ?

The derivative of g(u)=sqrt(6u)+sqrt(5u) is (sqrt(3))/(sqrt(2)\sqrt{u)}+(sqrt(5))/(2sqrt(u))

What is the first derivative of g(u)=sqrt(6u)+sqrt(5u) ?

The first derivative of g(u)=sqrt(6u)+sqrt(5u) is (sqrt(3))/(sqrt(2)\sqrt{u)}+(sqrt(5))/(2sqrt(u))

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derivative of

g (u) = 6 u + 5 u

\frac{3}{2 u} + \frac{5}{2 u}

Solution steps

\frac{d}{d u} (6 u + 5 u)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d u} (6 u) + \frac{d}{d u} (5 u)

\frac{d}{d u} (6 u) = \frac{3}{2 u}

\frac{d}{d u} (5 u) = \frac{5}{2 u}

= \frac{3}{2 u} + \frac{5}{2 u}

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What is the derivative of g(u)=sqrt(6u)+sqrt(5u) ?
The derivative of g(u)=sqrt(6u)+sqrt(5u) is (sqrt(3))/(sqrt(2)\sqrt{u)}+(sqrt(5))/(2sqrt(u))
What is the first derivative of g(u)=sqrt(6u)+sqrt(5u) ?
The first derivative of g(u)=sqrt(6u)+sqrt(5u) is (sqrt(3))/(sqrt(2)\sqrt{u)}+(sqrt(5))/(2sqrt(u))