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Frequently Asked Questions (FAQ)
What is the solution for y^{''}-2y^'=x+2e^x,y(0)=18,y^'(0)= 31/4 ?
- The solution for y^{''}-2y^'=x+2e^x,y(0)=18,y^'(0)= 31/4 is y=5e^{2x}+15+(-x^2-x)/4-2e^x