What is the tangent of f(x)= 4/(sqrt(x)),\at x= 1/4 ?

The tangent of f(x)= 4/(sqrt(x)),\at x= 1/4 is y=-16x+12

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tangent of f(x)= 4/(sqrt(x)),\at x= 1/4

tangent of

f (x) = \frac{4}{x}, at x = \frac{1}{4}

y = - 16 x + 12

Solution steps

Find the tangent point:

(\frac{1}{4}, 8)

Find the slope of

f (x) = \frac{4}{x} : \frac{df ( x )}{d x} = - \frac{2}{x ^{\frac{3}{2}}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 16

Find the line with slope m=

- 16

and passing through

(\frac{1}{4}, 8) : y = - 16 x + 12

y = - 16 x + 12

t an g e n t 5 2 x^{3} + 8 x (2.2)

n \to \infty lim (5 n e^{- n})

n = 1 \sum \infty \frac{4}{2 ^{n}}

\int \frac{x}{1 + x ^{4}} d x

\frac{d}{d x} (5 x y^{2})

What is the tangent of f(x)= 4/(sqrt(x)),\at x= 1/4 ?
The tangent of f(x)= 4/(sqrt(x)),\at x= 1/4 is y=-16x+12