What is the derivative of ln(5x^2+6) ?

The derivative of ln(5x^2+6) is (10x)/(5x^2+6)

What is the first derivative of ln(5x^2+6) ?

The first derivative of ln(5x^2+6) is (10x)/(5x^2+6)

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\frac{d}{d x} (ln (5 x^{2} + 6))

\frac{10 x}{5 x ^{2} + 6}

Solution steps

\frac{d}{d x} (ln (5 x^{2} + 6))

Apply the chain rule:

\frac{1}{5 x ^{2} + 6} \frac{d}{d x} (5 x^{2} + 6)

= \frac{1}{5 x ^{2} + 6} \frac{d}{d x} (5 x^{2} + 6)

\frac{d}{d x} (5 x^{2} + 6) = 10 x

= \frac{1}{5 x ^{2} + 6} \cdot 10 x

Simplify

\frac{1}{5 x ^{2} + 6} \cdot 10 x : \frac{10 x}{5 x ^{2} + 6}

= \frac{10 x}{5 x ^{2} + 6}

\frac{\partial}{\partial y} (x y + z)

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a \to \infty lim (a^{2})

\int t^{2} e^{4 t} d t

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What is the derivative of ln(5x^2+6) ?
The derivative of ln(5x^2+6) is (10x)/(5x^2+6)
What is the first derivative of ln(5x^2+6) ?
The first derivative of ln(5x^2+6) is (10x)/(5x^2+6)