What is the tangent of y=x-3x^2,(3,-24) ?

The tangent of y=x-3x^2,(3,-24) is y=-17x+27

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tangent of y=x-3x^2,(3,-24)

tangent of

y = x - 3 x^{2}, (3, - 24)

y = - 17 x + 27

Solution steps

Find the slope of

y = x - 3 x^{2} : \frac{d y}{d x} = 1 - 6 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 17

Find the line with slope m=

- 17

and passing through

(3, - 24) : y = - 17 x + 27

y = - 17 x + 27

\frac{\partial}{\partial x} (3 x^{2} y^{4} - 2)

\int (5 x - 7) e^{5 x - 7} d x

\frac{d}{d x} (\frac{2 + 3 x}{x ^{2}})

\int sin^{18} (x) cos^{3} (x) d x

d er i v a t i v e g (x) = 4 x^{2} (x^{3} + 5 x)

What is the tangent of y=x-3x^2,(3,-24) ?
The tangent of y=x-3x^2,(3,-24) is y=-17x+27