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Popular Calculus >

area y=4x-x^2,y=x,x=3

Solution

area

y = 4 x - x^{2}, y = x, x = 3

Solution

\frac{9}{2}

+1

Decimal

4.5

Solution steps

Apply the area formula:

\int_{0}^{3} - x^{2} + 3 x d x

Solve

\int_{0}^{3} - x^{2} + 3 x d x : \frac{9}{2}

The area is:

= \frac{9}{2}

Graph

Popular Examples

limit as x approaches infinity of 0/3

x \to \infty lim (\frac{0}{3})

derivative of f(x)=(sqrt(x))/(x^3+1)

d er i v a t i v e f (x) = \frac{x}{x ^{3} + 1}

integral of 3/(sqrt(x^2+16))

\int \frac{3}{x ^{2} + 16} d x

integral of 5x^{-4}

\int 5 x^{- 4} d x

tangent of f(x)= 3/x ,\at x=6

t an g e n t f (x) = \frac{3}{x}, at x = 6

Frequently Asked Questions (FAQ)

What is area y=4x-x^2,y=x,x=3 ?
The answer to area y=4x-x^2,y=x,x=3 is 9/2