y^'=3-2x-0.5y,y(0)=1

Lösung

y^{^{'}} = 3 - 2 x - 0.5 y, y (0) = 1

y = - 4 x + 14 - \frac{13}{e ^{0.5 x}}

Schritte zur Lösung

y^{'} (x) = 3 - 2 x - 0.5 y

Solve linear ODE:

y = - 4 x + 14 - \frac{13}{e ^{0.5 x}}

y = - 4 x + 14 - \frac{13}{e ^{0.5 x}}

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