derivative of cos(e^{4x})

Lösung

\frac{d}{d x} (cos (e^{4 x}))

- sin (e^{4 x}) e^{4 x} \cdot 4

Schritte zur Lösung

\frac{d}{d x} (cos (e^{4 x}))

Wende die Kettenregel an:

- sin (e^{4 x}) \frac{d}{d x} (e^{4 x})

= - sin (e^{4 x}) \frac{d}{d x} (e^{4 x})

\frac{d}{d x} (e^{4 x}) = e^{4 x} \cdot 4

= - sin (e^{4 x}) e^{4 x} \cdot 4

d er i v a t i v e f (x) = \frac{7 x ^{2} - 6 x + 1}{3 x + 2}

\frac{d ^{2}}{d x ^{2}} (3 + 5 x + 2 x^{2} + 0.4 x^{3})

y^{^{'}} = 4 x y

\int \frac{x ^{2} - x + 1}{( x ^{2} + 1 ) ^{3}} d x

d er i v a t i v e 3 e^{x} + \frac{8}{3 x}