integral of (9/x+6/(x^4))

Lösung

\int (\frac{9}{x} + \frac{6}{x ^{4}}) d x

9 ln ∣ x ∣ - \frac{2}{x ^{3}} + C

Schritte zur Lösung

\int \frac{9}{x} + \frac{6}{x ^{4}} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{9}{x} d x + \int \frac{6}{x ^{4}} d x

\int \frac{9}{x} d x = 9 ln ∣ x ∣

\int \frac{6}{x ^{4}} d x = - \frac{2}{x ^{3}}

= 9 ln ∣ x ∣ - \frac{2}{x ^{3}}

Füge eine Konstante zur Lösung hinzu

= 9 ln ∣ x ∣ - \frac{2}{x ^{3}} + C

(\frac{1}{x - 2})^{^{'}}

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d er i v a t i v e \frac{1 + X}{1 - X}

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