What is the integral of 3x^2+10x-5 ?

The integral of 3x^2+10x-5 is x^3+5x^2-5x+C

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integral of 3x^2+10x-5

\int 3 x^{2} + 10 x - 5 d x

x^{3} + 5 x^{2} - 5 x + C

Solution steps

\int 3 x^{2} + 10 x - 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{2} d x + \int 10 x d x - \int 5 d x

\int 3 x^{2} d x = x^{3}

\int 10 x d x = 5 x^{2}

\int 5 d x = 5 x

= x^{3} + 5 x^{2} - 5 x

Add a constant to the solution

= x^{3} + 5 x^{2} - 5 x + C

x \to - 2 - lim (- 3 x^{2} - 5 x + 3)

\int 10 csc^{2} (x) - sin (x) d x

cos (x), sin (2 x), x = 0, x = \frac{π}{2}

d er i v a t i v e ln (x) x

t an g e n t f (x) = x^{4} + 4 e^{x}, (0, 4)

What is the integral of 3x^2+10x-5 ?
The integral of 3x^2+10x-5 is x^3+5x^2-5x+C