What is the integral from 1 to infinity of x^{-1/7} ?

The integral from 1 to infinity of x^{-1/7} is diverges

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integral from 1 to infinity of x^{-1/7}

\int_{1}^{\infty} x^{- \frac{1}{7}} d x

diverges

Solution steps

\int_{1}^{\infty} x^{- \frac{1}{7}} d x

Compute the indefinite integral:

\int x^{- \frac{1}{7}} d x = \frac{7}{6} x^{\frac{6}{7}} + C

Compute the boundaries:

\int_{1}^{\infty} x^{- \frac{1}{7}} d x =

diverges

= diverges

\int \frac{x}{( x ^{2} + 2 ) ^{2}} d x

\int_{1}^{2} \frac{2}{x} d x

\int \frac{- 2}{x} d x

d er i v a t i v e \frac{15 + 5 5}{12} a^{3}

(1 + x^{2}) y^{^{''}} = 2 x (y^{^{'}})^{2}

What is the integral from 1 to infinity of x^{-1/7} ?
The integral from 1 to infinity of x^{-1/7} is diverges