What is the tangent of-3x^2-5x ?

The tangent of-3x^2-5x is y=(-6a_{0}-5)x+3a_{0}^2

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tangent of-3x^2-5x

tangent of

- 3 x^{2} - 5 x

y = (- 6 a_{0} - 5) x + 3 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 3 a_{0}^{2} - 5 a_{0})

Find the slope of

y = - 3 x^{2} - 5 x : \frac{d y}{d x} = - 6 x - 5

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 6 a_{0} - 5

Find the line with slope m=

- 6 a_{0} - 5

and passing through

(a_{0}, - 3 a_{0}^{2} - 5 a_{0}) : y = (- 6 a_{0} - 5) x + 3 a_{0}^{2}

y = (- 6 a_{0} - 5) x + 3 a_{0}^{2}

\frac{d}{d x} (\frac{x ^{2}}{x + 10})

n = 1 \sum \infty \frac{2}{n ^{2}}

\int \frac{x ^{2} + 5 x - 8}{x} d x

x \to \infty lim (2 x + 8)

\frac{d}{d x} (\frac{2 x}{1 + 4 x ^{2}})

What is the tangent of-3x^2-5x ?
The tangent of-3x^2-5x is y=(-6a_{0}-5)x+3a_{0}^2