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Beliebt Rechnen >

y^'=(x+y+4)^2

Lösung

y^{^{'}} = (x + y + 4)^{2}

Lösung

y = tan (x + c_{1}) - x - 4

Schritte zur Lösung

y^{'} (x) = (x + y + 4)^{2}

Solve using substitution:

y = tan (x + c_{1}) - x - 4

y = tan (x + c_{1}) - x - 4

Graph

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