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受欢迎的微积分 >

tangent 9x+2x^2

解答

切线

9 x + 2 x^{2}

解答

y = (9 + 4 a_{0}) x - 2 a_{0}^{2}

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, 9 a_{0} + 2 a_{0}^{2})

计算

y = 9 x + 2 x^{2}

的斜率:

\frac{d y}{d x} = 9 + 4 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 9 + 4 a_{0}

找到斜率 m=

9 + 4 a_{0}

且穿过

(a_{0}, 9 a_{0} + 2 a_{0}^{2})

的直线:

y = (9 + 4 a_{0}) x - 2 a_{0}^{2}

y = (9 + 4 a_{0}) x - 2 a_{0}^{2}

作图

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