x^2y^{''}+2xy^'+100.25y=0

Lösung

x^{2} y^{^{''}} + 2 x y^{^{'}} + 100.25 y = 0

y = \frac{c _{1} cos ( 10 ln ( x ) ) + c _{2} sin ( 10 ln ( x ) )}{x}

Schritte zur Lösung

x^{2} y^{''} (x) + 2 x y^{'} (x) + 100.25 y = 0

Solve linear ODE:

y = \frac{c _{1} cos ( 10 ln ( x ) ) + c _{2} sin ( 10 ln ( x ) )}{x}

y = \frac{c _{1} cos ( 10 ln ( x ) ) + c _{2} sin ( 10 ln ( x ) )}{x}

d er i v a t i v e f (x) = (ln (x))^{2}

y^{^{''}} - 4 y = e^{2 t}

\int_{\frac{1}{2}}^{3} 8 x ln (2 x) d x

t \to 0 lim (\frac{( tan ( t ) sec ( 2 t ) )}{3 t})

\frac{\partial}{\partial y} (x e^{x y} - 2 y + 1)