What is the limit as x approaches-1 of x^5+4x^2+x ?

The limit as x approaches-1 of x^5+4x^2+x is 2

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limit as x approaches-1 of x^5+4x^2+x

x \to - 1 lim (x^{5} + 4 x^{2} + x)

2

Solution steps

x \to - 1 lim (x^{5} + 4 x^{2} + x)

Plug in the value

x = - 1

= (- 1)^{5} + 4 (- 1)^{2} - 1

Simplify

(- 1)^{5} + 4 (- 1)^{2} - 1 : 2

= 2

\frac{d}{d x} (\frac{k}{x})

t an g e n t y = e^{x}, at x = ln (2)

x \to 1 lim (5 - x)

f (x) = 3 cos^{2} (x)

\frac{d}{d x} (a x^{2} (x - 4) + b x^{4} ln (\frac{x}{4}))

What is the limit as x approaches-1 of x^5+4x^2+x ?
The limit as x approaches-1 of x^5+4x^2+x is 2