What is (\partial)/(\partial x)(4xyarcsin(yz)) ?

The answer to (\partial)/(\partial x)(4xyarcsin(yz)) is 4yarcsin(yz)

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(\partial)/(\partial x)(4xyarcsin(yz))

\frac{\partial}{\partial x} (4 x y arcsin (yz))

4 y arcsin (yz)

Solution steps

\frac{\partial}{\partial x} (4 x y arcsin (yz))

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 y arcsin (yz) \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= 4 y arcsin (yz) \cdot 1

Simplify

= 4 y arcsin (yz)

\int \frac{8}{9 t 81 t ^{2} - 64} d t

\int (\frac{tan ( x )}{cot ( x )})^{3} d x

\frac{\partial}{\partial x} (y e^{y} - x e^{x})

x \to 3 lim (x^{2} - 5 x + 6)

(y^{3} - 2 x^{2} y) d x + (2 x^{3}) d y = 0

What is (\partial)/(\partial x)(4xyarcsin(yz)) ?
The answer to (\partial)/(\partial x)(4xyarcsin(yz)) is 4yarcsin(yz)