What is the tangent of f(x)=(2ln(x))/x ,\at x=1 ?

The tangent of f(x)=(2ln(x))/x ,\at x=1 is y=2x-2

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tangent of f(x)=(2ln(x))/x ,\at x=1

tangent of

f (x) = \frac{2 ln ( x )}{x}, at x = 1

y = 2 x - 2

Solution steps

Find the tangent point:

(1, 0)

Find the slope of

f (x) = \frac{2 ln ( x )}{x} : \frac{df ( x )}{d x} = \frac{2 ( 1 - ln ( x ) )}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(1, 0) : y = 2 x - 2

y = 2 x - 2

\frac{d}{d x} (\frac{sin ( 8 x )}{e ^{4 x}})

x \to 0 lim (\frac{5 ^{x} - 1 3 ^{x}}{x})

x \to 0 lim (x \cdot sin (\frac{1}{x}))

\frac{\partial}{\partial x} (ln (x) - 4)

\frac{\partial}{\partial x} (4 sin (4 x) e^{3 x})

What is the tangent of f(x)=(2ln(x))/x ,\at x=1 ?
The tangent of f(x)=(2ln(x))/x ,\at x=1 is y=2x-2