What is the derivative of xe^x+e^x ?

The derivative of xe^x+e^x is e^xx+2e^x

What is the first derivative of xe^x+e^x ?

The first derivative of xe^x+e^x is e^xx+2e^x

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derivative of

x e^{x} + e^{x}

e^{x} x + 2 e^{x}

Solution steps

\frac{d}{d x} (x e^{x} + e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x e^{x}) + \frac{d}{d x} (e^{x})

\frac{d}{d x} (x e^{x}) = e^{x} + e^{x} x

\frac{d}{d x} (e^{x}) = e^{x}

= e^{x} + e^{x} x + e^{x}

Simplify

= e^{x} x + 2 e^{x}

\frac{d y}{d x} = \frac{- x ^{2} y}{1 + x ^{3}}

\frac{d}{d t} (1 + (t - y)^{2})

x \to 6 lim (\frac{x ^{2} - 3}{x - 6})

\frac{\partial}{\partial x} (\frac{2}{x - 3})

d er i v a t i v e 2 arcsin (x^{4})

What is the derivative of xe^x+e^x ?
The derivative of xe^x+e^x is e^xx+2e^x
What is the first derivative of xe^x+e^x ?
The first derivative of xe^x+e^x is e^xx+2e^x