What is the derivative of 7/(3x^2) ?

The derivative of 7/(3x^2) is -(14)/(3x^3)

What is the first derivative of 7/(3x^2) ?

The first derivative of 7/(3x^2) is -(14)/(3x^3)

derivative of

\frac{7}{3 x ^{2}}

- \frac{14}{3 x ^{3}}

Solution steps

\frac{d}{d x} (\frac{7}{3 x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{7}{3} \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{7}{3} \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{7}{3} (- 2 x^{- 2 - 1})

Simplify

\frac{7}{3} (- 2 x^{- 2 - 1}) : - \frac{14}{3 x ^{3}}

= - \frac{14}{3 x ^{3}}

\frac{\partial}{\partial x} (sin^{3} (2 x))

\int_{0}^{π} 3 x sin (x) d x

in v erse l a pl a ce \frac{s}{s ^{4} + 4}

\frac{d}{d x} (20 cos (x))

\frac{\partial}{\partial x} (5 x^{2} + y^{2})

What is the derivative of 7/(3x^2) ?
The derivative of 7/(3x^2) is -(14)/(3x^3)
What is the first derivative of 7/(3x^2) ?
The first derivative of 7/(3x^2) is -(14)/(3x^3)