What is the solution for y^{''}-3y^'+2y=e^{3x} ?

The solution for y^{''}-3y^'+2y=e^{3x} is y=c_{1}e^{2x}+c_{2}e^x+1/2 e^{3x}

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y^{''}-3y^'+2y=e^{3x}

y^{^{''}} - 3 y^{^{'}} + 2 y = e^{3 x}

y = c_{1} e^{2 x} + c_{2} e^{x} + \frac{1}{2} e^{3 x}

Solution steps

y^{''} (x) - 3 y^{'} (x) + 2 y = e^{3 x}

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{x} + \frac{1}{2} e^{3 x}

y = c_{1} e^{2 x} + c_{2} e^{x} + \frac{1}{2} e^{3 x}

x \to \infty lim (\frac{1}{x} + 5)

\int sin (9 x) cos (7 x) d x

\int x cos^{2} (7 x) d x

(sin (5 x))^{^{'}}

s l o p e f (x) = x + \frac{1}{x}

What is the solution for y^{''}-3y^'+2y=e^{3x} ?
The solution for y^{''}-3y^'+2y=e^{3x} is y=c_{1}e^{2x}+c_{2}e^x+1/2 e^{3x}