What is the derivative of ax^n ?

The derivative of ax^n is anx^{n-1}

What is the first derivative of ax^n ?

The first derivative of ax^n is anx^{n-1}

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\frac{d}{d x} (a x^{n})

an x^{n - 1}

Solution steps

\frac{d}{d x} (a x^{n})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= a \frac{d}{d x} (x^{n})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= an x^{n - 1}

k = 1 \sum \infty \frac{k !}{2 ^{k}}

\int 15 tan^{2} (x) sec^{3} (x) d x

d er i v a t i v e 2 x e^{4 x}

\int \frac{2}{x ^{3} x ^{2} - 3} d x

d er i v a t i v e 2 x + 3 x

What is the derivative of ax^n ?
The derivative of ax^n is anx^{n-1}
What is the first derivative of ax^n ?
The first derivative of ax^n is anx^{n-1}