What is the integral from 0 to pi of cos(x)-sin(x) ?

The integral from 0 to pi of cos(x)-sin(x) is -2

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integral from 0 to pi of cos(x)-sin(x)

\int_{0}^{π} cos (x) - sin (x) d x

- 2

Solution steps

\int_{0}^{π} cos (x) - sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{π} cos (x) d x - \int_{0}^{π} sin (x) d x

\int_{0}^{π} cos (x) d x = 0

\int_{0}^{π} sin (x) d x = 2

= 0 - 2

Simplify

= - 2

\int x^{2} (5^{3} + 7^{2} - 6 x - 3) d x

\int x^{2} + x + 6 d x

\int \frac{3 x ^{2} + 5 x}{( x - 1 ) ( x + 1 ) ^{2}} d x

x^{2} y^{^{''}} - 3 x y^{^{'}} + 4 y = x, y (1) = 0, y^{^{'}} (1) = 0

n = 1 \sum \infty n! (2 x - 1)^{n}

What is the integral from 0 to pi of cos(x)-sin(x) ?
The integral from 0 to pi of cos(x)-sin(x) is -2