What is area y=x^2+2x-11,y=3,[3,5] ?

The answer to area y=x^2+2x-11,y=3,[3,5] is 62/3

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area y=x^2+2x-11,y=3,[3,5]

area

y = x^{2} + 2 x - 11, y = 3, [3, 5]

\frac{62}{3}

Decimal

20.66666 \dots

Solution steps

Apply the area formula:

\int_{3}^{5} x^{2} + 2 x - 14 d x

Solve

\int_{3}^{5} x^{2} + 2 x - 14 d x : \frac{62}{3}

The area is:

= \frac{62}{3}

\frac{\partial}{\partial x} (4 x sin (7 x^{2} y))

\frac{d}{d x} (x (x - 1) (x - 2))

d er i v a t i v e y = 7 x

y^{^{'}} + 5 y = t e^{(4 t)}

\frac{\partial}{\partial x} (3 x^{2} - 4)

What is area y=x^2+2x-11,y=3,[3,5] ?
The answer to area y=x^2+2x-11,y=3,[3,5] is 62/3