What is the solution for (dy)/(dx)=((y-1))/(x^2) ?

The solution for (dy)/(dx)=((y-1))/(x^2) is y=e^{-1/x+c_{1}}+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(dy)/(dx)=((y-1))/(x^2)

\frac{d y}{d x} = \frac{( y - 1 )}{x ^{2}}

y = e^{- \frac{1}{x} + c_{1}} + 1

Solution steps

\frac{d y}{d x} = \frac{( y - 1 )}{x ^{2}}

Solve separable ODE:

y = e^{- \frac{1}{x} + c_{1}} + 1

y = e^{- \frac{1}{x} + c_{1}} + 1

d er i v a t i v e 6 cos (2 x)

\int \frac{100}{36 + 25 x ^{2}} d x

n = 1 \sum \infty n e^{- n}

2 y^{^{'}} = y^{3} \cdot cos (x)

x y^{^{'}} + 2 y = - 4 cos (x)

What is the solution for (dy)/(dx)=((y-1))/(x^2) ?
The solution for (dy)/(dx)=((y-1))/(x^2) is y=e^{-1/x+c_{1}}+1