tangent f(x)=x^2,(1,-3)

Lösung

tangente von

f (x) = x^{2}, (1, - 3)

y = 6 x - 9 or y = - 2 x - 1

Schritte zur Lösung

Steigung der Tangente an

(1, - 3) : m = \frac{x ^{2} + 3}{x - 1}

Finde die Steigung von

f (x) = x^{2} : m = 2 x

Löse

2 x = \frac{x ^{2} + 3}{x - 1} : x = 3, x = - 1

Finde die Tangente an

x = 3 : y = 6 x - 9

Finde die Tangente an

x = - 1 : y = - 2 x - 1

y = 6 x - 9 or y = - 2 x - 1

\frac{\partial}{\partial x} (x^{2} sin (k x))

\frac{d}{d x} (e^{x} + e^{- 2 x})

y^{^{''}} + y^{^{'}} - 2 y = x^{3} - e^{- x}

\frac{d}{d x} (cos (x) + ln (tan (\frac{x}{2})))

\frac{d}{d y} (ln (x^{2} + y^{2} + z^{2}))