What is the derivative of x^4+(y-2^3) ?

The derivative of x^4+(y-2^3) is 4x^3+3(y-2)^2(dy)/(dx)

What is the first derivative of x^4+(y-2^3) ?

The first derivative of x^4+(y-2^3) is 4x^3+3(y-2)^2(dy)/(dx)

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\frac{d}{d x} (x^{4} + (y - 2)^{3})

4 x^{3} + 3 (y - 2)^{2} \frac{d y}{d x}

Solution steps

\frac{d}{d x} (x^{4} + (y - 2)^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} ((y - 2)^{3})

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} ((y - 2)^{3}) = 3 (y - 2)^{2} \frac{d y}{d x}

= 4 x^{3} + 3 (y - 2)^{2} \frac{d y}{d x}

\int x sin^{2} (9 x) d x

2 x^{\frac{3}{2}}

\int_{1}^{2} \frac{x ^{2} + 7}{3 x - x ^{2}} d x

t an g e n t f (x) = x^{3} - x, (- 1, 0)

\int \frac{1}{3 x + 8} d x

What is the derivative of x^4+(y-2^3) ?
The derivative of x^4+(y-2^3) is 4x^3+3(y-2)^2(dy)/(dx)
What is the first derivative of x^4+(y-2^3) ?
The first derivative of x^4+(y-2^3) is 4x^3+3(y-2)^2(dy)/(dx)