y^{''}=-3y-2y^'

Lösung

y^{^{''}} = - 3 y - 2 y^{^{'}}

y = e^{- t} (c_{1} cos (2 t) + c_{2} sin (2 t))

Schritte zur Lösung

y^{''} (t) = - 3 y - 2 y^{'} (t)

Solve linear ODE:

y = e^{- t} (c_{1} cos (2 t) + c_{2} sin (2 t))

y = e^{- t} (c_{1} cos (2 t) + c_{2} sin (2 t))

d er i v a t i v e \frac{5}{e ^{x}}

d er i v a t i v e \frac{t - t}{t ^{\frac{1}{4}}}

d er i v a t i v e f (\frac{1}{2}) = 10 + 12 x - 3 x^{2} - x^{3}

x \to 1 lim (\frac{x ^{3 a} - 3 a x + 3 a - 1}{( x - 1 ) ^{2}})

\frac{d}{d x} (ln^{3} (sec (2^{3 x})))