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Beliebt Rechnen >

sum from n=1 to infinity of 1/(1.05^n)*1

Lösung

n = 1 \sum \infty \frac{1}{1.0 5 ^{n}} \cdot 1

Lösung

20

Schritte zur Lösung

n = 1 \sum \infty \frac{1}{1.0 5 ^{n}} \cdot 1

Vereinfache

= n = 1 \sum \infty \frac{1}{1.0 5 ^{n}}

n = k \sum \infty (a_{n}) = n = 0 \sum \infty (a_{n}) - a_{0} - a_{1} - \dots a_{k - 1}

= n = 0 \sum \infty \frac{1}{1.0 5 ^{n}} - \frac{1}{1.0 5 ^{0}}

n = 0 \sum \infty \frac{1}{1.0 5 ^{n}} = 21

= 21 - \frac{1}{1.0 5 ^{0}}

Vereinfache

= 20

Beliebte Beispiele

derivative of 2ln(3x^2-1)

\frac{d}{d x} (2 ln (3 x^{2} - 1))

derivative of-19x^2+4x+22

\frac{d}{d x} (- 19 x^{2} + 4 x + 22)

derivative g(x)=x^5-2x

d er i v a t i v e g (x) = x^{5} - 2 x

integral of 1/(x^2-x+6)

\int \frac{1}{x ^{2} - x + 6} d x

integral of e^{-xy}

\int e^{- x y} d y