(\partial)/(\partial x)(e^x+e^{-x})

Lösung

\frac{\partial}{\partial x} (e^{x} + e^{- x})

e^{x} - e^{- x}

Schritte zur Lösung

\frac{\partial}{\partial x} (e^{x} + e^{- x})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (e^{x}) + \frac{\partial}{\partial x} (e^{- x})

\frac{\partial}{\partial x} (e^{x}) = e^{x}

\frac{\partial}{\partial x} (e^{- x}) = - e^{- x}

= e^{x} - e^{- x}

\frac{d}{d x} (3 x^{2} + x + 4)

\int_{1}^{4} x^{- \frac{3}{2}} d x

\int_{0}^{4} \frac{5 π y ^{4}}{4} d y

\int \frac{x cos ( x ^{2} )}{sin ( x ^{2} )} d x

y^{^{''}} + 26 y^{^{'}} + 6 y = 0