What is the tangent of 9x^2+2x,\at x=3 ?

The tangent of 9x^2+2x,\at x=3 is y=56x-81

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tangent of 9x^2+2x,\at x=3

tangent of

9 x^{2} + 2 x, at x = 3

y = 56 x - 81

Solution steps

Find the tangent point:

(3, 87)

Find the slope of

y = 9 x^{2} + 2 x : \frac{d y}{d x} = 18 x + 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 56

Find the line with slope m=

56

and passing through

(3, 87) : y = 56 x - 81

y = 56 x - 81

n or ma l y = x^{3} - 3 x + 3, (2, 5)

\frac{d}{d x} (sin (0))

\frac{d}{d x} (\frac{1}{( x - 1 ) ^{2}})

d er i v a t i v e 3 x - 3 x

d er i v a t i v e \frac{4 x ^{2} + 2 x + 4}{x}

What is the tangent of 9x^2+2x,\at x=3 ?
The tangent of 9x^2+2x,\at x=3 is y=56x-81