What is the derivative of x^2-4x+9 ?

The derivative of x^2-4x+9 is 2x-4

What is the first derivative of x^2-4x+9 ?

The first derivative of x^2-4x+9 is 2x-4

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\frac{d}{d x} (x^{2} - 4 x + 9)

2 x - 4

Solution steps

\frac{d}{d x} (x^{2} - 4 x + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (9)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (9) = 0

= 2 x - 4 + 0

Simplify

= 2 x - 4

y^{^{''}} + 4 y^{^{'}} + 4 y = e^{- 2 x} + x^{2}

\frac{d y}{d x} = 13 x^{12} y

\frac{d}{d x} (arcsin (\frac{x - 2}{1}))

\int_{2}^{6} π (y - 2) 2 d y

\frac{d y}{d x} = \frac{cos ( 5 x )}{e ^{5 y}}

What is the derivative of x^2-4x+9 ?
The derivative of x^2-4x+9 is 2x-4
What is the first derivative of x^2-4x+9 ?
The first derivative of x^2-4x+9 is 2x-4