derivative of acos(x+bsin(x))

Lösung

\frac{d}{d x} (a \cdot cos (x) + b \cdot sin (x))

- a sin (x) + b cos (x)

Schritte zur Lösung

\frac{d}{d x} (a cos (x) + b sin (x))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a cos (x)) + \frac{d}{d x} (b sin (x))

\frac{d}{d x} (a cos (x)) = - a sin (x)

\frac{d}{d x} (b sin (x)) = b cos (x)

= - a sin (x) + b cos (x)

\int (2 (z + 1) e^{2 x - 2} + 2 y) d x

\frac{d}{d x} (A x e^{4 x})

\frac{d}{d x} (\frac{1}{6} (x - 1) (x + 5)^{5} + 10)

t an g e n t y = 9 x^{2} + 9 x - 3

d er i v a t i v e f (x) = sin (1 + cos (x))