What is the derivative of cos(3x^2-2x) ?

The derivative of cos(3x^2-2x) is -sin(3x^2-2x)(6x-2)

What is the first derivative of cos(3x^2-2x) ?

The first derivative of cos(3x^2-2x) is -sin(3x^2-2x)(6x-2)

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\frac{d}{d x} (cos (3 x^{2} - 2 x))

- sin (3 x^{2} - 2 x) (6 x - 2)

Solution steps

\frac{d}{d x} (cos (3 x^{2} - 2 x))

Apply the chain rule:

- sin (3 x^{2} - 2 x) \frac{d}{d x} (3 x^{2} - 2 x)

= - sin (3 x^{2} - 2 x) \frac{d}{d x} (3 x^{2} - 2 x)

\frac{d}{d x} (3 x^{2} - 2 x) = 6 x - 2

= - sin (3 x^{2} - 2 x) (6 x - 2)

\int \frac{x ^{3}}{5 x ^{4} - 1} d x

\int (3 x + 4)^{3} d x

d er i v a t i v e \frac{1}{x ^{2} - 1}

\frac{d}{d x} (1 + \frac{1}{x})

x y^{^{'}} = y + 8 x^{2} sin (x), y (π) = 0

What is the derivative of cos(3x^2-2x) ?
The derivative of cos(3x^2-2x) is -sin(3x^2-2x)(6x-2)
What is the first derivative of cos(3x^2-2x) ?
The first derivative of cos(3x^2-2x) is -sin(3x^2-2x)(6x-2)