What is the derivative of tan(sqrt(x)+1) ?

The derivative of tan(sqrt(x)+1) is (sec^2(sqrt(x)+1))/(2sqrt(x))

What is the first derivative of tan(sqrt(x)+1) ?

The first derivative of tan(sqrt(x)+1) is (sec^2(sqrt(x)+1))/(2sqrt(x))

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derivative of

tan (x + 1)

\frac{sec ^{2} ( x + 1 )}{2 x}

Solution steps

\frac{d}{d x} (tan (x + 1))

Apply the chain rule:

sec^{2} (x + 1) \frac{d}{d x} (x + 1)

= sec^{2} (x + 1) \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = \frac{1}{2 x}

= sec^{2} (x + 1) \frac{1}{2 x}

Simplify

sec^{2} (x + 1) \frac{1}{2 x} : \frac{sec ^{2} ( x + 1 )}{2 x}

= \frac{sec ^{2} ( x + 1 )}{2 x}

\frac{d}{d x} (ln (3 + x))

\frac{d}{d x} ((3 x + 4) x^{2})

\int \frac{1}{n ^{2} + 1}

\int x cos (x y) d y

\frac{d}{d x} (ln (4 x^{2} + 1))

What is the derivative of tan(sqrt(x)+1) ?
The derivative of tan(sqrt(x)+1) is (sec^2(sqrt(x)+1))/(2sqrt(x))
What is the first derivative of tan(sqrt(x)+1) ?
The first derivative of tan(sqrt(x)+1) is (sec^2(sqrt(x)+1))/(2sqrt(x))