What is (\partial}{\partial t}(\frac{s-3r)/t) ?

The answer to (\partial}{\partial t}(\frac{s-3r)/t) is -(s-3r)/(t^2)

(\partial}{\partial t}(\frac{s-3r)/t)

\frac{\partial}{\partial t} (\frac{s - 3 r}{t})

- \frac{s - 3 r}{t ^{2}}

Solution steps

\frac{\partial}{\partial t} (\frac{s - 3 r}{t})

Treat

s, r

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (s - 3 r) \frac{\partial}{\partial t} (\frac{1}{t})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= (s - 3 r) \frac{\partial}{\partial t} (t^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= (s - 3 r) (- 1 \cdot t^{- 1 - 1})

Simplify

(s - 3 r) (- 1 \cdot t^{- 1 - 1}) : - \frac{s - 3 r}{t ^{2}}

= - \frac{s - 3 r}{t ^{2}}

y^{^{''}} - y = x

\frac{d}{d x} (\frac{7}{3 x ^{4}})

x \to 8 lim (\frac{x - 8}{x})

x \to \infty lim (\frac{6 x ^{2}}{e ^{5 x}})

\frac{\partial}{\partial x} (ln ∣ x y ∣)

What is (\partial}{\partial t}(\frac{s-3r)/t) ?
The answer to (\partial}{\partial t}(\frac{s-3r)/t) is -(s-3r)/(t^2)