What is the derivative of 6e^x+2/(\sqrt[3]{x)} ?

The derivative of 6e^x+2/(\sqrt[3]{x)} is 6e^x-2/(3x^{4/3)}

What is the first derivative of 6e^x+2/(\sqrt[3]{x)} ?

The first derivative of 6e^x+2/(\sqrt[3]{x)} is 6e^x-2/(3x^{4/3)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative of

6 e^{x} + \frac{2}{3 x}

6 e^{x} - \frac{2}{3 x ^{\frac{4}{3}}}

Solution steps

\frac{d}{d x} (6 e^{x} + \frac{2}{3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 e^{x}) + \frac{d}{d x} (\frac{2}{3 x})

\frac{d}{d x} (6 e^{x}) = 6 e^{x}

\frac{d}{d x} (\frac{2}{3 x}) = - \frac{2}{3 x ^{\frac{4}{3}}}

= 6 e^{x} - \frac{2}{3 x ^{\frac{4}{3}}}

\int \frac{1}{( 1 - x ) ^{6}} d x

t an g e n t \frac{- 8 x}{x ^{2} + 1} (0)

\int sec^{2} (3 x) d x

\int cos^{2} (4 t) d t

t a y l or x^{- 2}, 5

What is the derivative of 6e^x+2/(\sqrt[3]{x)} ?
The derivative of 6e^x+2/(\sqrt[3]{x)} is 6e^x-2/(3x^{4/3)}
What is the first derivative of 6e^x+2/(\sqrt[3]{x)} ?
The first derivative of 6e^x+2/(\sqrt[3]{x)} is 6e^x-2/(3x^{4/3)}