y(x-y-2)dx+x(y-x+4)dy=0

Lösung

y (x - y - 2) d x + x (y - x + 4) d y = 0

y = \frac{- x + x ( x - 2 c _{1} ( - x + 4 ) )}{2 c _{1}}, y = - \frac{x + x ( x - 2 c _{1} ( - x + 4 ) )}{2 c _{1}}

Schritte zur Lösung

y (x - y - 2) d x + x (y - x + 4) d y = 0

Solve exact ODE:

y = \frac{- x + x ( x - 2 c _{1} ( - x + 4 ) )}{2 c _{1}}, y = - \frac{x + x ( x - 2 c _{1} ( - x + 4 ) )}{2 c _{1}}

y = \frac{- x + x ( x - 2 c _{1} ( - x + 4 ) )}{2 c _{1}}, y = - \frac{x + x ( x - 2 c _{1} ( - x + 4 ) )}{2 c _{1}}

e^{2} y \frac{d y}{d x} = e^{- y} + e^{- 2 x - y}

\frac{d}{d x} (ln (cos (sin (e^{x^{3}}))))

y^{^{''''}} + 13 y^{^{''}} + 36 y = 0

a re a y = 2 x + 24, y = x^{2}

y^{^{''}} + \frac{3}{x} y^{^{'}} - \frac{15}{x ^{2}} y = 0