What is the integral of 2/(x^{0.85)} ?

The integral of 2/(x^{0.85)} is 13.33333…x^{0.15}+C

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integral of 2/(x^{0.85)}

\int \frac{2}{x ^{0.85}} d x

13.33333 \dots x^{0.15} + C

Solution steps

\int \frac{2}{x ^{0.85}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1}{x ^{0.85}} d x

Apply the Power Rule

= 2 \cdot 6.66666 \dots x^{0.15}

Simplify

= 13.33333 \dots x^{0.15}

Add a constant to the solution

= 13.33333 \dots x^{0.15} + C

\frac{\partial}{\partial x} (2 x y + x f (x, y) (\frac{y}{x}))

\frac{\partial}{\partial y} (3 + 2 x y)

a re a 5 x, 3 x^{2}

\frac{\partial}{\partial x} (2 cos (x^{2} + y^{2}))

\frac{d}{d x} (x + 13)

What is the integral of 2/(x^{0.85)} ?
The integral of 2/(x^{0.85)} is 13.33333…x^{0.15}+C